6/22/2023 0 Comments Power of ten questions![]() Traditional teaching fails to actively involve students. Learning and understanding Mathematics, at every level, requires Lesson Finishers then sign up for a subscription now: Newsletter, unlock the printable worksheets and see our Maths To the thousands of Transum resources, receive our monthly If you would like to enjoy ad-free access Have access to reports of the Transum Trophies earned by class Plans and assessment data in the Class Admin application and Subscribers can manage class lists, lesson Transum Topic pages and the facility to add to the collection The teacher with access to quality external links on each of the To the online exercises, quizzes and puzzles. Logged in to their Transum subscription on this computer.Ī Transum subscription unlocks the answers They are available in this space to teachers, tutors and parents Create your own map as you go deeper and deeper into this maze of rooms looking for the clues to find the treasure room. Transum breaking news is available on Twitter and if that's not enough there is also a Transum Facebook page.Ī mathematical adventure game in the enigmatic home of Transum. You can listen to the podcast while you are commuting, exercising or relaxing. The newsletter is then duplicated as a podcast which is available on the major delivery networks. Keep up the good work and thank you very muchĮach month a newsletter is published containing details of the new additions to the Transum website and a new puzzle of the month. Have particularly enjoyed KIM's game, as we have not used that for Mathematics before. We use them for all age groups and abilities. These starters have saved my time and have made my lessons enjoyable."Ĭomment recorded on the 25 June 'Starter of the Day' page by and, : They are of immence help and the students enjoy them very much. "I am thankful for providing such wonderful starters. AreĬomment recorded on the 6 May 'Starter of the Day' page by Natalie, London: The people who enjoy how mystifying, puzzling and hard it is. '0.Mathematicians are not the people who find Maths easy they are The preparation: f = ]īenchmark with kaya3's exponent n = 200 as well as n = -200 as negative exponent with nonzero result and n = -5000 / n = 5000 as medium-size negative/positive exponents from your original range: n = 200ġ28 ns 129 ns 130 ns 10.0 ** n if n < 309 else infħ2 ns 73 ns 73 ns 0.0 if n < -323 else f if n < 309 else infġ30 ns 130 ns 131 ns 10.0 ** n if n < 309 else infħ6 ns 76 ns 76 ns 0.0 if n < -323 else f if n < 309 else infġ19 ns 120 ns 120 ns 10.0 ** n if n < 309 else infģ4 ns 34 ns 34 ns 0.0 if n < -323 else f if n < 309 else infģ3 ns 33 ns 33 ns 10.0 ** n if n < 309 else infĥ3 ns 53 ns 53 ns 0.0 if n < -323 else f if n < 309 else infīenchmark code ( Try it online!): from timeit import repeat So the fastest of these options in both cases is the obvious one: 10 ** n for integers and 10.0 ** n for floats.Īnother contender for the floats case, precompute all possible nonzero finite results and look them up: 0.0 if n < -323 else f if n < 309 else inf > timeit('f(n)', setup='n = 200 from functools import partial import numpy as np f = partial(np.power, 10.0, dtype=float)') > timeit('np.power(10.0, n, dtype=float)', setup='n = 200 import numpy as np') 10 ** n computes an integer (when n is non-negative), whereas float(f'1e")', setup='n = 200') So is the f-string actually the best way to go about it? I guess the f-string approach is the fastest because nothing is actually calculated, though it only works for integer powers of ten, whereas the other methods are more complicated operations that also work with any real number as the base and power. # ValueError: Integers to negative integer powers are not allowed. # "dtype=float" is necessary because otherwise it will raise: 'np.pow': partial(np.power, 10, dtype=float) If as the input you provide the (integer) power, what is the fastest way to create the corresponding power of ten? Here are four alternatives I could come up with, and the fastest way seems to be using an f-string: from functools import partial
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